Tool Bounds
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ app(app(plus(), app(s(), x)), y) ->
app(s(), app(app(plus(), x), y))
, app(plus(), 0()) -> id()
, app(id(), x) -> x}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool CDI
stdout:
TIMEOUT
Statistics:
Number of monomials: 2435
Last formula building started for bound 3
Last SAT solving started for bound 3Tool EDA
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ app(app(plus(), app(s(), x)), y) ->
app(s(), app(app(plus(), x), y))
, app(plus(), 0()) -> id()
, app(id(), x) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following EDA-non-satisfying matrix interpretation:
Interpretation Functions:
id() = [2]
[0]
app(x1, x2) = [1 1] x1 + [1 0] x2 + [0]
[0 1] [0 1] [0]
plus() = [1]
[1]
0() = [3]
[3]
s() = [1]
[3]
Hurray, we answered YES(?,O(n^2))Tool IDA
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ app(app(plus(), app(s(), x)), y) ->
app(s(), app(app(plus(), x), y))
, app(plus(), 0()) -> id()
, app(id(), x) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following EDA-non-satisfying and IDA(2)-non-satisfying matrix interpretation:
Interpretation Functions:
id() = [1]
[0]
app(x1, x2) = [1 2] x1 + [1 0] x2 + [0]
[0 1] [0 1] [0]
plus() = [0]
[0]
0() = [2]
[0]
s() = [0]
[2]
Hurray, we answered YES(?,O(n^2))Tool TRI
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ app(app(plus(), app(s(), x)), y) ->
app(s(), app(app(plus(), x), y))
, app(plus(), 0()) -> id()
, app(id(), x) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
id() = [2]
[0]
app(x1, x2) = [1 1] x1 + [1 0] x2 + [0]
[0 1] [0 1] [3]
plus() = [3]
[0]
0() = [1]
[2]
s() = [3]
[0]
Hurray, we answered YES(?,O(n^2))Tool TRI2
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ app(app(plus(), app(s(), x)), y) ->
app(s(), app(app(plus(), x), y))
, app(plus(), 0()) -> id()
, app(id(), x) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
id() = [0]
[0]
app(x1, x2) = [1 1] x1 + [1 0] x2 + [2]
[0 1] [0 1] [3]
plus() = [0]
[0]
0() = [2]
[0]
s() = [0]
[0]
Hurray, we answered YES(?,O(n^2))