Tool Bounds
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs: {app(app(apply(), f), x) -> app(f, x)}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
The problem is match-bounded by 1.
The enriched problem is compatible with the following automaton:
{ apply_0() -> 1
, app_0(1, 1) -> 1
, app_1(1, 1) -> 1}
Hurray, we answered YES(?,O(n^1))Tool CDI
stdout:
YES(?,O(n^2))
QUADRATIC upper bound on the derivational complexity
This TRS is terminating using the deltarestricted interpretation
apply(delta) = + 0 + 2*delta
app(delta, X1, X0) = + 0*X0 + 0*X1 + 0 + 3*X0*delta + 3*X1*delta + 0*delta
app_tau_1(delta) = delta/(0 + 3 * delta)
app_tau_2(delta) = delta/(0 + 3 * delta)
Time: 0.095472 seconds
Statistics:
Number of monomials: 61
Last formula building started for bound 3
Last SAT solving started for bound 3Tool EDA
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs: {app(app(apply(), f), x) -> app(f, x)}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
We have the following EDA-non-satisfying matrix interpretation:
Interpretation Functions:
apply() = [0]
app(x1, x2) = [1] x1 + [1] x2 + [3]
Hurray, we answered YES(?,O(n^1))Tool IDA
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs: {app(app(apply(), f), x) -> app(f, x)}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
Interpretation Functions:
apply() = [0]
app(x1, x2) = [1] x1 + [1] x2 + [3]
Hurray, we answered YES(?,O(n^1))Tool TRI
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs: {app(app(apply(), f), x) -> app(f, x)}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
apply() = [0]
app(x1, x2) = [1] x1 + [1] x2 + [3]
Hurray, we answered YES(?,O(n^1))Tool TRI2
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs: {app(app(apply(), f), x) -> app(f, x)}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
apply() = [3]
[0]
app(x1, x2) = [1 3] x1 + [1 3] x2 + [2]
[0 0] [0 1] [3]
Hurray, we answered YES(?,O(n^2))