Tool Bounds
Execution Time | 3.1186104e-2ms |
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Answer | YES(?,O(n^1)) |
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Input | Der95 02 |
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stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs:
{ .(y, .(i(y), z)) -> z
, .(i(y), .(y, z)) -> z
, i(i(x)) -> x
, i(1()) -> 1()
, .(x, i(x)) -> 1()
, .(i(x), x) -> 1()
, .(x, 1()) -> x
, .(1(), x) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
The problem is match-bounded by 1.
The enriched problem is compatible with the following automaton:
{ 1_0() -> 1
, 1_1() -> 1
, ._0(1, 1) -> 1
, i_0(1) -> 1}
Hurray, we answered YES(?,O(n^1))Tool CDI
Execution Time | 0.335114ms |
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Answer | YES(?,O(n^2)) |
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Input | Der95 02 |
---|
stdout:
YES(?,O(n^2))
QUADRATIC upper bound on the derivational complexity
This TRS is terminating using the deltarestricted interpretation
i(delta, X0) = + 1*X0 + 0 + 0*X0*delta + 2*delta
1(delta) = + 0 + 1*delta
.(delta, X1, X0) = + 1*X0 + 1*X1 + 0 + 0*X0*delta + 0*X1*delta + 0*delta
i_tau_1(delta) = delta/(1 + 0 * delta)
._tau_1(delta) = delta/(1 + 0 * delta)
._tau_2(delta) = delta/(1 + 0 * delta)
Time: 0.295943 seconds
Statistics:
Number of monomials: 297
Last formula building started for bound 3
Last SAT solving started for bound 3Tool EDA
Execution Time | 0.16859007ms |
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Answer | YES(?,O(n^1)) |
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Input | Der95 02 |
---|
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs:
{ .(y, .(i(y), z)) -> z
, .(i(y), .(y, z)) -> z
, i(i(x)) -> x
, i(1()) -> 1()
, .(x, i(x)) -> 1()
, .(i(x), x) -> 1()
, .(x, 1()) -> x
, .(1(), x) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
We have the following EDA-non-satisfying matrix interpretation:
Interpretation Functions:
1() = [0]
.(x1, x2) = [1] x1 + [1] x2 + [2]
i(x1) = [1] x1 + [1]
Hurray, we answered YES(?,O(n^1))Tool IDA
Execution Time | 0.27212882ms |
---|
Answer | YES(?,O(n^1)) |
---|
Input | Der95 02 |
---|
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs:
{ .(y, .(i(y), z)) -> z
, .(i(y), .(y, z)) -> z
, i(i(x)) -> x
, i(1()) -> 1()
, .(x, i(x)) -> 1()
, .(i(x), x) -> 1()
, .(x, 1()) -> x
, .(1(), x) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
Interpretation Functions:
1() = [0]
.(x1, x2) = [1] x1 + [1] x2 + [1]
i(x1) = [1] x1 + [1]
Hurray, we answered YES(?,O(n^1))Tool TRI
Execution Time | 6.708217e-2ms |
---|
Answer | YES(?,O(n^1)) |
---|
Input | Der95 02 |
---|
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs:
{ .(y, .(i(y), z)) -> z
, .(i(y), .(y, z)) -> z
, i(i(x)) -> x
, i(1()) -> 1()
, .(x, i(x)) -> 1()
, .(i(x), x) -> 1()
, .(x, 1()) -> x
, .(1(), x) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
1() = [0]
.(x1, x2) = [1] x1 + [1] x2 + [2]
i(x1) = [1] x1 + [1]
Hurray, we answered YES(?,O(n^1))Tool TRI2
Execution Time | 0.12351012ms |
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Answer | YES(?,O(n^2)) |
---|
Input | Der95 02 |
---|
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ .(y, .(i(y), z)) -> z
, .(i(y), .(y, z)) -> z
, i(i(x)) -> x
, i(1()) -> 1()
, .(x, i(x)) -> 1()
, .(i(x), x) -> 1()
, .(x, 1()) -> x
, .(1(), x) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
1() = [2]
[0]
.(x1, x2) = [1 0] x1 + [1 2] x2 + [2]
[0 1] [0 1] [1]
i(x1) = [1 0] x1 + [2]
[0 1] [0]
Hurray, we answered YES(?,O(n^2))