Tool Bounds
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs:
{p(p(b(a(x0)), x1), p(x2, x3)) ->
p(p(x3, a(x2)), p(b(a(x1)), b(x0)))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
The problem is match-bounded by 1.
The enriched problem is compatible with the following automaton:
{ a_0(1) -> 1
, a_1(1) -> 6
, a_1(1) -> 7
, a_1(2) -> 8
, a_1(4) -> 9
, a_1(7) -> 6
, a_1(9) -> 6
, b_0(1) -> 1
, b_1(1) -> 5
, b_1(6) -> 4
, p_0(1, 1) -> 1
, p_1(1, 7) -> 2
, p_1(2, 3) -> 1
, p_1(3, 8) -> 2
, p_1(4, 5) -> 3
, p_1(5, 9) -> 2}
Hurray, we answered YES(?,O(n^1))Tool CDI
stdout:
TIMEOUT
Statistics:
Number of monomials: 0
Last formula building started for bound 0
Last SAT solving started for bound 0Tool EDA
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{p(p(b(a(x0)), x1), p(x2, x3)) ->
p(p(x3, a(x2)), p(b(a(x1)), b(x0)))}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool IDA
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{p(p(b(a(x0)), x1), p(x2, x3)) ->
p(p(x3, a(x2)), p(b(a(x1)), b(x0)))}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool TRI
stdout:
YES(?,O(n^3))
We consider the following Problem:
Strict Trs:
{p(p(b(a(x0)), x1), p(x2, x3)) ->
p(p(x3, a(x2)), p(b(a(x1)), b(x0)))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^3))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
a(x1) = [1 0 0 0 0] x1 + [0]
[0 0 0 0 0] [0]
[0 0 0 0 0] [0]
[0 0 0 0 0] [0]
[0 0 0 0 1] [1]
b(x1) = [1 0 0 0 0] x1 + [0]
[0 0 0 0 0] [0]
[0 0 0 0 0] [0]
[0 0 0 0 2] [0]
[0 0 0 0 0] [0]
p(x1, x2) = [1 0 2 0 0] x1 + [1 2 0 2 0] x2 + [0]
[0 0 2 0 2] [0 1 1 0 0] [0]
[0 0 0 1 0] [0 0 0 2 0] [0]
[0 0 0 0 0] [0 0 0 0 0] [0]
[0 0 0 0 0] [0 0 0 0 1] [0]
Hurray, we answered YES(?,O(n^3))Tool TRI2
stdout:
MAYBE
We consider the following Problem:
Strict Trs:
{p(p(b(a(x0)), x1), p(x2, x3)) ->
p(p(x3, a(x2)), p(b(a(x1)), b(x0)))}
StartTerms: all
Strategy: none
Certificate: MAYBE
Proof:
The input cannot be shown compatible
Arrrr..