Tool Bounds
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs:
{p(p(b(a(x0)), x1), p(x2, x3)) ->
p(p(b(x2), a(a(b(x1)))), p(x3, x0))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
The problem is match-bounded by 1.
The enriched problem is compatible with the following automaton:
{ a_0(1) -> 1
, a_1(6) -> 5
, a_1(7) -> 6
, b_0(1) -> 1
, b_1(1) -> 4
, b_1(1) -> 7
, b_1(2) -> 4
, b_1(3) -> 4
, b_1(5) -> 7
, p_0(1, 1) -> 1
, p_1(1, 1) -> 3
, p_1(2, 3) -> 1
, p_1(2, 3) -> 3
, p_1(3, 1) -> 3
, p_1(4, 5) -> 2}
Hurray, we answered YES(?,O(n^1))Tool CDI
stdout:
TIMEOUT
Statistics:
Number of monomials: 0
Last formula building started for bound 0
Last SAT solving started for bound 0Tool EDA
stdout:
YES(?,O(n^3))
We consider the following Problem:
Strict Trs:
{p(p(b(a(x0)), x1), p(x2, x3)) ->
p(p(b(x2), a(a(b(x1)))), p(x3, x0))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^3))
Proof:
We have the following EDA-non-satisfying matrix interpretation:
Interpretation Functions:
a(x1) = [1 0 2] x1 + [0]
[0 1 0] [1]
[0 0 0] [0]
b(x1) = [1 0 0] x1 + [0]
[0 1 0] [0]
[0 0 0] [0]
p(x1, x2) = [1 2 0] x1 + [1 0 2] x2 + [0]
[0 0 0] [0 0 0] [0]
[0 0 0] [0 1 0] [0]
Hurray, we answered YES(?,O(n^3))Tool IDA
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{p(p(b(a(x0)), x1), p(x2, x3)) ->
p(p(b(x2), a(a(b(x1)))), p(x3, x0))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following EDA-non-satisfying and IDA(2)-non-satisfying matrix interpretation:
Interpretation Functions:
a(x1) = [1 0 2] x1 + [0]
[0 1 0] [2]
[0 0 0] [0]
b(x1) = [1 0 0] x1 + [0]
[0 1 0] [0]
[0 0 0] [0]
p(x1, x2) = [1 2 0] x1 + [1 0 2] x2 + [0]
[0 0 0] [0 0 0] [0]
[0 0 0] [0 1 0] [0]
Hurray, we answered YES(?,O(n^2))Tool TRI
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{p(p(b(a(x0)), x1), p(x2, x3)) ->
p(p(b(x2), a(a(b(x1)))), p(x3, x0))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
a(x1) = [1 2 0] x1 + [0]
[0 0 0] [0]
[0 0 1] [2]
b(x1) = [1 0 0] x1 + [0]
[0 0 0] [0]
[0 0 1] [0]
p(x1, x2) = [1 0 2] x1 + [1 1 0] x2 + [0]
[0 0 0] [0 0 2] [0]
[0 0 0] [0 0 0] [0]
Hurray, we answered YES(?,O(n^2))Tool TRI2
stdout:
MAYBE
We consider the following Problem:
Strict Trs:
{p(p(b(a(x0)), x1), p(x2, x3)) ->
p(p(b(x2), a(a(b(x1)))), p(x3, x0))}
StartTerms: all
Strategy: none
Certificate: MAYBE
Proof:
The input cannot be shown compatible
Arrrr..