Problem ICFP 2010 212062

Tool Bounds

Execution Time	60.123924ms
Answer	TIMEOUT
Input	ICFP 2010 212062

stdout:

TIMEOUT

We consider the following Problem:

  Strict Trs:
    {  5(4(3(0(0(x1))))) -> 1(0(4(0(3(5(x1))))))
     , 5(3(3(2(0(x1))))) -> 5(2(3(3(0(2(x1))))))
     , 5(1(4(0(0(x1))))) -> 0(2(5(0(1(4(x1))))))
     , 5(0(5(2(0(x1))))) -> 0(3(5(5(0(2(x1))))))
     , 3(3(5(2(0(x1))))) -> 4(3(3(5(0(2(x1))))))
     , 3(3(5(2(0(x1))))) -> 3(5(2(3(0(2(x1))))))
     , 0(3(5(2(0(x1))))) -> 3(0(2(5(3(0(x1))))))
     , 5(4(2(0(x1)))) -> 5(4(5(0(2(x1)))))
     , 5(4(2(0(x1)))) -> 5(0(2(2(4(x1)))))
     , 5(4(2(0(x1)))) -> 2(4(3(5(0(x1)))))
     , 5(4(0(0(x1)))) -> 0(4(5(5(0(2(x1))))))
     , 5(3(2(0(x1)))) -> 3(3(5(3(0(2(x1))))))
     , 5(3(2(0(x1)))) -> 5(3(0(1(2(x1)))))
     , 5(2(2(0(x1)))) -> 0(2(1(2(4(5(x1))))))
     , 5(1(5(0(x1)))) -> 5(1(0(3(5(x1)))))
     , 5(1(4(0(x1)))) -> 0(1(5(2(4(x1)))))
     , 5(1(0(0(x1)))) -> 0(3(1(0(1(5(x1))))))
     , 3(4(0(0(x1)))) -> 3(0(4(5(3(0(x1))))))
     , 3(4(0(0(x1)))) -> 0(3(3(0(4(5(x1))))))
     , 0(5(2(0(x1)))) -> 0(5(0(2(2(x1)))))
     , 5(2(0(x1))) -> 5(3(5(1(0(2(x1))))))
     , 5(2(0(x1))) -> 5(0(1(2(2(2(x1))))))
     , 5(2(0(x1))) -> 5(1(0(2(4(x1)))))
     , 5(2(0(x1))) -> 1(0(2(3(5(x1)))))
     , 5(2(0(x1))) -> 0(2(3(3(5(x1)))))
     , 5(2(0(x1))) -> 3(5(0(2(x1))))
     , 5(2(0(x1))) -> 0(2(3(5(x1))))
     , 3(0(0(x1))) -> 3(0(2(4(0(2(x1))))))
     , 3(0(0(x1))) -> 3(0(2(0(3(x1)))))
     , 0(0(0(x1))) -> 3(0(0(1(0(2(x1))))))
     , 0(0(0(x1))) -> 0(1(0(4(0(4(x1))))))
     , 0(0(x1)) -> 3(1(0(1(0(4(x1))))))
     , 0(0(x1)) -> 3(0(4(0(2(2(x1))))))
     , 0(0(x1)) -> 1(1(1(0(2(0(x1))))))
     , 0(0(x1)) -> 1(0(4(1(0(2(x1))))))
     , 0(0(x1)) -> 1(0(1(3(0(1(x1))))))
     , 0(0(x1)) -> 1(0(1(0(2(2(x1))))))
     , 0(0(x1)) -> 0(1(0(2(1(2(x1))))))
     , 0(0(x1)) -> 2(1(0(2(0(x1)))))
     , 0(0(x1)) -> 1(0(2(2(0(x1)))))
     , 0(0(x1)) -> 1(0(2(0(3(x1)))))
     , 0(0(x1)) -> 1(0(1(2(0(x1)))))
     , 0(0(x1)) -> 1(0(1(0(1(x1)))))
     , 0(0(x1)) -> 1(0(2(0(x1))))
     , 0(0(x1)) -> 0(1(0(2(x1))))}
  StartTerms: all
  Strategy: none

Certificate: TIMEOUT

Proof:
  Computation stopped due to timeout after 60.0 seconds.

Arrrr..

Tool CDI

Execution Time	60.048336ms
Answer	TIMEOUT
Input	ICFP 2010 212062

stdout:

TIMEOUT

Statistics:
Number of monomials: 0
Last formula building started for bound 0
Last SAT solving started for bound 0

Tool EDA

Execution Time	60.085037ms
Answer	TIMEOUT
Input	ICFP 2010 212062

stdout:

Tool IDA

Execution Time	60.076828ms
Answer	TIMEOUT
Input	ICFP 2010 212062

stdout:

Tool TRI

Execution Time	60.066628ms
Answer	TIMEOUT
Input	ICFP 2010 212062

stdout:

Tool TRI2

Execution Time	10.257717ms
Answer	MAYBE
Input	ICFP 2010 212062

stdout:

MAYBE

We consider the following Problem:

  Strict Trs:
    {  5(4(3(0(0(x1))))) -> 1(0(4(0(3(5(x1))))))
     , 5(3(3(2(0(x1))))) -> 5(2(3(3(0(2(x1))))))
     , 5(1(4(0(0(x1))))) -> 0(2(5(0(1(4(x1))))))
     , 5(0(5(2(0(x1))))) -> 0(3(5(5(0(2(x1))))))
     , 3(3(5(2(0(x1))))) -> 4(3(3(5(0(2(x1))))))
     , 3(3(5(2(0(x1))))) -> 3(5(2(3(0(2(x1))))))
     , 0(3(5(2(0(x1))))) -> 3(0(2(5(3(0(x1))))))
     , 5(4(2(0(x1)))) -> 5(4(5(0(2(x1)))))
     , 5(4(2(0(x1)))) -> 5(0(2(2(4(x1)))))
     , 5(4(2(0(x1)))) -> 2(4(3(5(0(x1)))))
     , 5(4(0(0(x1)))) -> 0(4(5(5(0(2(x1))))))
     , 5(3(2(0(x1)))) -> 3(3(5(3(0(2(x1))))))
     , 5(3(2(0(x1)))) -> 5(3(0(1(2(x1)))))
     , 5(2(2(0(x1)))) -> 0(2(1(2(4(5(x1))))))
     , 5(1(5(0(x1)))) -> 5(1(0(3(5(x1)))))
     , 5(1(4(0(x1)))) -> 0(1(5(2(4(x1)))))
     , 5(1(0(0(x1)))) -> 0(3(1(0(1(5(x1))))))
     , 3(4(0(0(x1)))) -> 3(0(4(5(3(0(x1))))))
     , 3(4(0(0(x1)))) -> 0(3(3(0(4(5(x1))))))
     , 0(5(2(0(x1)))) -> 0(5(0(2(2(x1)))))
     , 5(2(0(x1))) -> 5(3(5(1(0(2(x1))))))
     , 5(2(0(x1))) -> 5(0(1(2(2(2(x1))))))
     , 5(2(0(x1))) -> 5(1(0(2(4(x1)))))
     , 5(2(0(x1))) -> 1(0(2(3(5(x1)))))
     , 5(2(0(x1))) -> 0(2(3(3(5(x1)))))
     , 5(2(0(x1))) -> 3(5(0(2(x1))))
     , 5(2(0(x1))) -> 0(2(3(5(x1))))
     , 3(0(0(x1))) -> 3(0(2(4(0(2(x1))))))
     , 3(0(0(x1))) -> 3(0(2(0(3(x1)))))
     , 0(0(0(x1))) -> 3(0(0(1(0(2(x1))))))
     , 0(0(0(x1))) -> 0(1(0(4(0(4(x1))))))
     , 0(0(x1)) -> 3(1(0(1(0(4(x1))))))
     , 0(0(x1)) -> 3(0(4(0(2(2(x1))))))
     , 0(0(x1)) -> 1(1(1(0(2(0(x1))))))
     , 0(0(x1)) -> 1(0(4(1(0(2(x1))))))
     , 0(0(x1)) -> 1(0(1(3(0(1(x1))))))
     , 0(0(x1)) -> 1(0(1(0(2(2(x1))))))
     , 0(0(x1)) -> 0(1(0(2(1(2(x1))))))
     , 0(0(x1)) -> 2(1(0(2(0(x1)))))
     , 0(0(x1)) -> 1(0(2(2(0(x1)))))
     , 0(0(x1)) -> 1(0(2(0(3(x1)))))
     , 0(0(x1)) -> 1(0(1(2(0(x1)))))
     , 0(0(x1)) -> 1(0(1(0(1(x1)))))
     , 0(0(x1)) -> 1(0(2(0(x1))))
     , 0(0(x1)) -> 0(1(0(2(x1))))}
  StartTerms: all
  Strategy: none

Certificate: MAYBE

Proof:
  The input cannot be shown compatible

Arrrr..