Tool Bounds
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs:
{ 5(5(5(5(5(5(4(4(4(4(4(4(x1)))))))))))) -> 2(x1)
, 4(5(4(5(x1)))) -> 4(4(5(5(x1))))
, 0(x1) -> 1(x1)}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
The problem is match-bounded by 1.
The enriched problem is compatible with the following automaton:
{ 0_0(1) -> 1
, 1_0(1) -> 1
, 1_1(1) -> 1
, 5_0(1) -> 1
, 5_1(1) -> 4
, 5_1(4) -> 3
, 4_0(1) -> 1
, 4_1(2) -> 1
, 4_1(3) -> 2
, 2_0(1) -> 1
, 2_1(1) -> 1
, 2_1(1) -> 3
, 2_1(1) -> 4
, 2_1(2) -> 1
, 2_1(2) -> 3
, 2_1(2) -> 4
, 2_1(3) -> 1
, 2_1(3) -> 3
, 2_1(3) -> 4}
Hurray, we answered YES(?,O(n^1))Tool CDI
stdout:
TIMEOUT
Statistics:
Number of monomials: 0
Last formula building started for bound 0
Last SAT solving started for bound 0Tool EDA
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ 5(5(5(5(5(5(4(4(4(4(4(4(x1)))))))))))) -> 2(x1)
, 4(5(4(5(x1)))) -> 4(4(5(5(x1))))
, 0(x1) -> 1(x1)}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool IDA
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ 5(5(5(5(5(5(4(4(4(4(4(4(x1)))))))))))) -> 2(x1)
, 4(5(4(5(x1)))) -> 4(4(5(5(x1))))
, 0(x1) -> 1(x1)}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool TRI
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ 5(5(5(5(5(5(4(4(4(4(4(4(x1)))))))))))) -> 2(x1)
, 4(5(4(5(x1)))) -> 4(4(5(5(x1))))
, 0(x1) -> 1(x1)}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
0(x1) = [1 3] x1 + [3]
[0 1] [3]
1(x1) = [1 3] x1 + [2]
[0 1] [3]
5(x1) = [1 0] x1 + [0]
[0 0] [1]
4(x1) = [1 1] x1 + [1]
[0 0] [0]
2(x1) = [1 1] x1 + [1]
[0 0] [1]
Hurray, we answered YES(?,O(n^2))Tool TRI2
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ 5(5(5(5(5(5(4(4(4(4(4(4(x1)))))))))))) -> 2(x1)
, 4(5(4(5(x1)))) -> 4(4(5(5(x1))))
, 0(x1) -> 1(x1)}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
0(x1) = [1 3] x1 + [3]
[0 1] [3]
1(x1) = [1 3] x1 + [2]
[0 1] [3]
5(x1) = [1 2] x1 + [0]
[0 1] [2]
4(x1) = [1 0] x1 + [0]
[0 1] [2]
2(x1) = [1 0] x1 + [3]
[0 1] [0]
Hurray, we answered YES(?,O(n^2))