Tool Bounds
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ r1(cons(x, k), a) -> r1(k, cons(x, a))
, r1(empty(), a) -> a
, rev(ls) -> r1(ls, empty())}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool CDI
stdout:
YES(?,O(n^2))
QUADRATIC upper bound on the derivational complexity
This TRS is terminating using the deltarestricted interpretation
cons(delta, X1, X0) = + 1*X0 + 0*X1 + 2 + 0*X0*delta + 1*X1*delta + 0*delta
rev(delta, X0) = + 1*X0 + 3 + 2*X0*delta + 1*delta
empty(delta) = + 3 + 0*delta
r1(delta, X1, X0) = + 1*X0 + 1*X1 + 0 + 0*X0*delta + 2*X1*delta + 0*delta
cons_tau_1(delta) = delta/(0 + 1 * delta)
cons_tau_2(delta) = delta/(1 + 0 * delta)
rev_tau_1(delta) = delta/(1 + 2 * delta)
r1_tau_1(delta) = delta/(1 + 2 * delta)
r1_tau_2(delta) = delta/(1 + 0 * delta)
Time: 0.079819 seconds
Statistics:
Number of monomials: 136
Last formula building started for bound 3
Last SAT solving started for bound 3Tool EDA
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ r1(cons(x, k), a) -> r1(k, cons(x, a))
, r1(empty(), a) -> a
, rev(ls) -> r1(ls, empty())}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following EDA-non-satisfying matrix interpretation:
Interpretation Functions:
rev(x1) = [1 2] x1 + [3]
[0 1] [3]
empty() = [0]
[1]
r1(x1, x2) = [1 2] x1 + [1 0] x2 + [0]
[0 1] [0 1] [2]
cons(x1, x2) = [1 0] x1 + [1 0] x2 + [0]
[0 0] [0 1] [2]
Hurray, we answered YES(?,O(n^2))Tool IDA
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ r1(cons(x, k), a) -> r1(k, cons(x, a))
, r1(empty(), a) -> a
, rev(ls) -> r1(ls, empty())}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following EDA-non-satisfying and IDA(2)-non-satisfying matrix interpretation:
Interpretation Functions:
rev(x1) = [1 2] x1 + [3]
[0 1] [3]
empty() = [0]
[1]
r1(x1, x2) = [1 2] x1 + [1 0] x2 + [0]
[0 1] [0 1] [2]
cons(x1, x2) = [1 0] x1 + [1 0] x2 + [0]
[0 0] [0 1] [2]
Hurray, we answered YES(?,O(n^2))Tool TRI
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ r1(cons(x, k), a) -> r1(k, cons(x, a))
, r1(empty(), a) -> a
, rev(ls) -> r1(ls, empty())}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
rev(x1) = [1 3] x1 + [3]
[0 1] [3]
empty() = [0]
[0]
r1(x1, x2) = [1 2] x1 + [1 0] x2 + [1]
[0 1] [0 1] [2]
cons(x1, x2) = [1 1] x1 + [1 0] x2 + [3]
[0 0] [0 1] [2]
Hurray, we answered YES(?,O(n^2))Tool TRI2
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ r1(cons(x, k), a) -> r1(k, cons(x, a))
, r1(empty(), a) -> a
, rev(ls) -> r1(ls, empty())}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
rev(x1) = [1 3] x1 + [3]
[0 1] [3]
empty() = [0]
[0]
r1(x1, x2) = [1 2] x1 + [1 0] x2 + [1]
[0 1] [0 1] [2]
cons(x1, x2) = [1 1] x1 + [1 0] x2 + [3]
[0 0] [0 1] [2]
Hurray, we answered YES(?,O(n^2))