Tool Bounds
Execution Time | 3.3493042e-2ms |
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Answer | YES(?,O(n^1)) |
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Input | SK90 4.37 |
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stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs: {a(b(a(x))) -> b(a(x))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
The problem is match-bounded by 2.
The enriched problem is compatible with the following automaton:
{ a_0(1) -> 1
, a_1(1) -> 2
, a_2(1) -> 3
, b_0(1) -> 1
, b_1(2) -> 1
, b_1(2) -> 2
, b_1(2) -> 3
, b_2(3) -> 2
, b_2(3) -> 3}
Hurray, we answered YES(?,O(n^1))Tool CDI
Execution Time | 0.2625599ms |
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Answer | YES(?,O(n^2)) |
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Input | SK90 4.37 |
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stdout:
YES(?,O(n^2))
QUADRATIC upper bound on the derivational complexity
This TRS is terminating using the deltarestricted interpretation
a(delta, X0) = + 1*X0 + 0 + 1*X0*delta + 0*delta
b(delta, X0) = + 0*X0 + 2 + 2*X0*delta + 0*delta
a_tau_1(delta) = delta/(1 + 1 * delta)
b_tau_1(delta) = delta/(0 + 2 * delta)
Time: 0.225079 seconds
Statistics:
Number of monomials: 93
Last formula building started for bound 3
Last SAT solving started for bound 3Tool EDA
Execution Time | 5.759096e-2ms |
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Answer | YES(?,O(n^1)) |
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Input | SK90 4.37 |
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stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs: {a(b(a(x))) -> b(a(x))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
We have the following EDA-non-satisfying matrix interpretation:
Interpretation Functions:
a(x1) = [1] x1 + [2]
b(x1) = [1] x1 + [0]
Hurray, we answered YES(?,O(n^1))Tool IDA
Execution Time | 0.17445993ms |
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Answer | YES(?,O(n^1)) |
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Input | SK90 4.37 |
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stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs: {a(b(a(x))) -> b(a(x))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
Interpretation Functions:
a(x1) = [1] x1 + [2]
b(x1) = [1] x1 + [0]
Hurray, we answered YES(?,O(n^1))Tool TRI
Execution Time | 7.584381e-2ms |
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Answer | YES(?,O(n^1)) |
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Input | SK90 4.37 |
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stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs: {a(b(a(x))) -> b(a(x))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
a(x1) = [1] x1 + [2]
b(x1) = [1] x1 + [0]
Hurray, we answered YES(?,O(n^1))Tool TRI2
Execution Time | 7.0206165e-2ms |
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Answer | YES(?,O(n^1)) |
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Input | SK90 4.37 |
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stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs: {a(b(a(x))) -> b(a(x))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^1))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
a(x1) = [1 0] x1 + [2]
[0 0] [2]
b(x1) = [1 2] x1 + [0]
[0 0] [0]
Hurray, we answered YES(?,O(n^1))