Tool Bounds
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ a(y, c(b(a(0(), x), 0()))) -> b(a(c(b(0(), y)), x), 0())
, a(y, x) -> y
, b(x, y) -> c(a(c(y), a(0(), x)))}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool CDI
stdout:
TIMEOUT
Statistics:
Number of monomials: 0
Last formula building started for bound 0
Last SAT solving started for bound 0Tool EDA
stdout:
YES(?,O(n^3))
We consider the following Problem:
Strict Trs:
{ a(y, c(b(a(0(), x), 0()))) -> b(a(c(b(0(), y)), x), 0())
, a(y, x) -> y
, b(x, y) -> c(a(c(y), a(0(), x)))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^3))
Proof:
We have the following EDA-non-satisfying matrix interpretation:
Interpretation Functions:
b(x1, x2) = [1 0 0] x1 + [1 1 0] x2 + [3]
[0 1 0] [0 0 0] [0]
[0 0 0] [0 0 0] [0]
c(x1) = [1 1 0] x1 + [0]
[0 0 0] [0]
[0 0 0] [0]
0() = [0]
[0]
[1]
a(x1, x2) = [1 1 0] x1 + [1 0 0] x2 + [1]
[0 1 3] [0 0 0] [0]
[0 0 1] [0 0 0] [0]
Hurray, we answered YES(?,O(n^3))Tool IDA
stdout:
YES(?,O(n^3))
We consider the following Problem:
Strict Trs:
{ a(y, c(b(a(0(), x), 0()))) -> b(a(c(b(0(), y)), x), 0())
, a(y, x) -> y
, b(x, y) -> c(a(c(y), a(0(), x)))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^3))
Proof:
We have the following EDA-non-satisfying and IDA(3)-non-satisfying matrix interpretation:
Interpretation Functions:
b(x1, x2) = [1 1 0] x1 + [1 0 0] x2 + [3]
[0 0 0] [0 0 0] [0]
[0 0 0] [0 0 0] [0]
c(x1) = [1 0 0] x1 + [0]
[0 0 0] [0]
[0 0 0] [0]
0() = [0]
[2]
[1]
a(x1, x2) = [1 0 0] x1 + [1 0 0] x2 + [1]
[0 1 3] [0 0 0] [0]
[0 0 1] [0 0 0] [0]
Hurray, we answered YES(?,O(n^3))Tool TRI
stdout:
YES(?,O(n^3))
We consider the following Problem:
Strict Trs:
{ a(y, c(b(a(0(), x), 0()))) -> b(a(c(b(0(), y)), x), 0())
, a(y, x) -> y
, b(x, y) -> c(a(c(y), a(0(), x)))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^3))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
b(x1, x2) = [1 0 0] x1 + [1 2 0] x2 + [3]
[0 1 0] [0 0 0] [0]
[0 0 0] [0 0 0] [0]
c(x1) = [1 1 0] x1 + [0]
[0 0 0] [0]
[0 0 0] [0]
0() = [0]
[0]
[2]
a(x1, x2) = [1 2 0] x1 + [1 0 0] x2 + [1]
[0 1 2] [0 0 0] [0]
[0 0 1] [0 0 0] [0]
Hurray, we answered YES(?,O(n^3))Tool TRI2
stdout:
MAYBE
We consider the following Problem:
Strict Trs:
{ a(y, c(b(a(0(), x), 0()))) -> b(a(c(b(0(), y)), x), 0())
, a(y, x) -> y
, b(x, y) -> c(a(c(y), a(0(), x)))}
StartTerms: all
Strategy: none
Certificate: MAYBE
Proof:
The input cannot be shown compatible
Arrrr..