Tool Bounds
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ g(f(x, y), 0()) -> f(g(x, 0()), g(y, 0()))
, g(s(x), y) -> g(f(x, y), 0())
, g(x, s(y)) -> g(f(x, y), 0())
, g(0(), f(x, x)) -> x}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool CDI
stdout:
MAYBE
Statistics:
Number of monomials: 2045
Last formula building started for bound 3
Last SAT solving started for bound 3Tool EDA
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ g(f(x, y), 0()) -> f(g(x, 0()), g(y, 0()))
, g(s(x), y) -> g(f(x, y), 0())
, g(x, s(y)) -> g(f(x, y), 0())
, g(0(), f(x, x)) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following EDA-non-satisfying matrix interpretation:
Interpretation Functions:
0() = [0]
[0]
f(x1, x2) = [1 0] x1 + [1 0] x2 + [0]
[0 1] [0 1] [1]
g(x1, x2) = [1 2] x1 + [1 2] x2 + [0]
[0 1] [0 1] [0]
s(x1) = [1 0] x1 + [2]
[0 1] [1]
Hurray, we answered YES(?,O(n^2))Tool IDA
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ g(f(x, y), 0()) -> f(g(x, 0()), g(y, 0()))
, g(s(x), y) -> g(f(x, y), 0())
, g(x, s(y)) -> g(f(x, y), 0())
, g(0(), f(x, x)) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following EDA-non-satisfying and IDA(2)-non-satisfying matrix interpretation:
Interpretation Functions:
0() = [0]
[0]
f(x1, x2) = [1 0] x1 + [1 0] x2 + [0]
[0 1] [0 1] [1]
g(x1, x2) = [1 1] x1 + [1 2] x2 + [0]
[0 1] [0 1] [0]
s(x1) = [1 0] x1 + [0]
[0 1] [2]
Hurray, we answered YES(?,O(n^2))Tool TRI
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ g(f(x, y), 0()) -> f(g(x, 0()), g(y, 0()))
, g(s(x), y) -> g(f(x, y), 0())
, g(x, s(y)) -> g(f(x, y), 0())
, g(0(), f(x, x)) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
0() = [0]
[0]
f(x1, x2) = [1 0] x1 + [1 0] x2 + [0]
[0 1] [0 1] [1]
g(x1, x2) = [1 1] x1 + [1 1] x2 + [0]
[0 1] [0 1] [0]
s(x1) = [1 0] x1 + [3]
[0 1] [1]
Hurray, we answered YES(?,O(n^2))Tool TRI2
stdout:
YES(?,O(n^2))
We consider the following Problem:
Strict Trs:
{ g(f(x, y), 0()) -> f(g(x, 0()), g(y, 0()))
, g(s(x), y) -> g(f(x, y), 0())
, g(x, s(y)) -> g(f(x, y), 0())
, g(0(), f(x, x)) -> x}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^2))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
0() = [0]
[0]
f(x1, x2) = [1 0] x1 + [1 0] x2 + [1]
[0 1] [0 1] [1]
g(x1, x2) = [1 1] x1 + [1 1] x2 + [0]
[0 1] [0 1] [0]
s(x1) = [1 0] x1 + [3]
[0 1] [1]
Hurray, we answered YES(?,O(n^2))