Tool Bounds
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ max(N(L(x), N(y, z))) -> max(N(L(x), L(max(N(y, z)))))
, max(N(L(s(x)), L(s(y)))) -> s(max(N(L(x), L(y))))
, max(N(L(0()), L(y))) -> y
, max(L(x)) -> x}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool CDI
stdout:
TIMEOUT
Statistics:
Number of monomials: 0
Last formula building started for bound 0
Last SAT solving started for bound 0Tool EDA
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ max(N(L(x), N(y, z))) -> max(N(L(x), L(max(N(y, z)))))
, max(N(L(s(x)), L(s(y)))) -> s(max(N(L(x), L(y))))
, max(N(L(0()), L(y))) -> y
, max(L(x)) -> x}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool IDA
stdout:
MAYBE
We consider the following Problem:
Strict Trs:
{ max(N(L(x), N(y, z))) -> max(N(L(x), L(max(N(y, z)))))
, max(N(L(s(x)), L(s(y)))) -> s(max(N(L(x), L(y))))
, max(N(L(0()), L(y))) -> y
, max(L(x)) -> x}
StartTerms: all
Strategy: none
Certificate: MAYBE
Proof:
None of the processors succeeded.
Details of failed attempt(s):
-----------------------------
1) 'matrix-interpretation of dimension 2' failed due to the following reason:
The input cannot be shown compatible
2) 'matrix-interpretation of dimension 2' failed due to the following reason:
The input cannot be shown compatible
3) 'matrix-interpretation of dimension 1' failed due to the following reason:
The input cannot be shown compatible
Arrrr..Tool TRI
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ max(N(L(x), N(y, z))) -> max(N(L(x), L(max(N(y, z)))))
, max(N(L(s(x)), L(s(y)))) -> s(max(N(L(x), L(y))))
, max(N(L(0()), L(y))) -> y
, max(L(x)) -> x}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool TRI2
stdout:
MAYBE
We consider the following Problem:
Strict Trs:
{ max(N(L(x), N(y, z))) -> max(N(L(x), L(max(N(y, z)))))
, max(N(L(s(x)), L(s(y)))) -> s(max(N(L(x), L(y))))
, max(N(L(0()), L(y))) -> y
, max(L(x)) -> x}
StartTerms: all
Strategy: none
Certificate: MAYBE
Proof:
The input cannot be shown compatible
Arrrr..