Tool Bounds
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ C(c(x1)) -> x1
, c(C(x1)) -> x1
, B(b(x1)) -> x1
, b(B(x1)) -> x1
, A(a(x1)) -> x1
, a(A(x1)) -> x1
, B(C(a(x1))) -> a(C(B(x1)))
, A(c(b(x1))) -> b(c(A(x1)))
, c(A(B(x1))) -> B(A(c(x1)))
, b(a(C(x1))) -> C(a(b(x1)))
, C(B(A(x1))) -> A(B(C(x1)))
, a(b(c(x1))) -> c(b(a(x1)))}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool CDI
stdout:
MAYBE
Statistics:
Number of monomials: 2112
Last formula building started for bound 3
Last SAT solving started for bound 3Tool EDA
stdout:
YES(?,O(n^3))
We consider the following Problem:
Strict Trs:
{ C(c(x1)) -> x1
, c(C(x1)) -> x1
, B(b(x1)) -> x1
, b(B(x1)) -> x1
, A(a(x1)) -> x1
, a(A(x1)) -> x1
, B(C(a(x1))) -> a(C(B(x1)))
, A(c(b(x1))) -> b(c(A(x1)))
, c(A(B(x1))) -> B(A(c(x1)))
, b(a(C(x1))) -> C(a(b(x1)))
, C(B(A(x1))) -> A(B(C(x1)))
, a(b(c(x1))) -> c(b(a(x1)))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^3))
Proof:
We have the following EDA-non-satisfying matrix interpretation:
Interpretation Functions:
c(x1) = [1 2 0] x1 + [0]
[0 0 1] [0]
[0 1 0] [1]
b(x1) = [1 0 2] x1 + [0]
[0 0 1] [0]
[0 1 0] [2]
a(x1) = [1 0 1] x1 + [0]
[0 0 1] [3]
[0 1 0] [0]
A(x1) = [1 2 0] x1 + [0]
[0 0 1] [0]
[0 1 0] [2]
B(x1) = [1 0 1] x1 + [0]
[0 0 1] [0]
[0 1 0] [2]
C(x1) = [1 0 1] x1 + [0]
[0 0 1] [1]
[0 1 0] [1]
Hurray, we answered YES(?,O(n^3))Tool IDA
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ C(c(x1)) -> x1
, c(C(x1)) -> x1
, B(b(x1)) -> x1
, b(B(x1)) -> x1
, A(a(x1)) -> x1
, a(A(x1)) -> x1
, B(C(a(x1))) -> a(C(B(x1)))
, A(c(b(x1))) -> b(c(A(x1)))
, c(A(B(x1))) -> B(A(c(x1)))
, b(a(C(x1))) -> C(a(b(x1)))
, C(B(A(x1))) -> A(B(C(x1)))
, a(b(c(x1))) -> c(b(a(x1)))}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool TRI
stdout:
YES(?,O(n^3))
We consider the following Problem:
Strict Trs:
{ C(c(x1)) -> x1
, c(C(x1)) -> x1
, B(b(x1)) -> x1
, b(B(x1)) -> x1
, A(a(x1)) -> x1
, a(A(x1)) -> x1
, B(C(a(x1))) -> a(C(B(x1)))
, A(c(b(x1))) -> b(c(A(x1)))
, c(A(B(x1))) -> B(A(c(x1)))
, b(a(C(x1))) -> C(a(b(x1)))
, C(B(A(x1))) -> A(B(C(x1)))
, a(b(c(x1))) -> c(b(a(x1)))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^3))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
c(x1) = [1 0 2] x1 + [0]
[0 1 0] [0]
[0 0 1] [0]
b(x1) = [1 0 1] x1 + [0]
[0 1 0] [1]
[0 0 1] [0]
a(x1) = [1 1 0] x1 + [0]
[0 1 0] [2]
[0 0 1] [0]
A(x1) = [1 2 0] x1 + [0]
[0 1 0] [1]
[0 0 1] [0]
B(x1) = [1 1 0] x1 + [0]
[0 1 0] [0]
[0 0 1] [2]
C(x1) = [1 0 0] x1 + [1]
[0 1 0] [0]
[0 0 1] [2]
Hurray, we answered YES(?,O(n^3))Tool TRI2
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ C(c(x1)) -> x1
, c(C(x1)) -> x1
, B(b(x1)) -> x1
, b(B(x1)) -> x1
, A(a(x1)) -> x1
, a(A(x1)) -> x1
, B(C(a(x1))) -> a(C(B(x1)))
, A(c(b(x1))) -> b(c(A(x1)))
, c(A(B(x1))) -> B(A(c(x1)))
, b(a(C(x1))) -> C(a(b(x1)))
, C(B(A(x1))) -> A(B(C(x1)))
, a(b(c(x1))) -> c(b(a(x1)))}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..