Problem Zantema 06 14

Tool Bounds

Execution Time60.06484ms
Answer
TIMEOUT
InputZantema 06 14

stdout:

TIMEOUT

We consider the following Problem:

  Strict Trs:
    {  b(c(x1)) -> c(x1)
     , a(b(x1)) -> b(a(x1))
     , c(c(x1)) -> c(b(a(x1)))
     , b(b(x1)) -> a(c(b(x1)))
     , a(a(x1)) -> b(a(b(x1)))}
  StartTerms: all
  Strategy: none

Certificate: TIMEOUT

Proof:
  Computation stopped due to timeout after 60.0 seconds.

Arrrr..

Tool CDI

Execution Time1.5113599ms
Answer
MAYBE
InputZantema 06 14

stdout:

MAYBE

Statistics:
Number of monomials: 439
Last formula building started for bound 3
Last SAT solving started for bound 3

Tool EDA

Execution Time60.03395ms
Answer
TIMEOUT
InputZantema 06 14

stdout:

TIMEOUT

We consider the following Problem:

  Strict Trs:
    {  b(c(x1)) -> c(x1)
     , a(b(x1)) -> b(a(x1))
     , c(c(x1)) -> c(b(a(x1)))
     , b(b(x1)) -> a(c(b(x1)))
     , a(a(x1)) -> b(a(b(x1)))}
  StartTerms: all
  Strategy: none

Certificate: TIMEOUT

Proof:
  Computation stopped due to timeout after 60.0 seconds.

Arrrr..

Tool IDA

Execution Time60.03389ms
Answer
TIMEOUT
InputZantema 06 14

stdout:

TIMEOUT

We consider the following Problem:

  Strict Trs:
    {  b(c(x1)) -> c(x1)
     , a(b(x1)) -> b(a(x1))
     , c(c(x1)) -> c(b(a(x1)))
     , b(b(x1)) -> a(c(b(x1)))
     , a(a(x1)) -> b(a(b(x1)))}
  StartTerms: all
  Strategy: none

Certificate: TIMEOUT

Proof:
  Computation stopped due to timeout after 60.0 seconds.

Arrrr..

Tool TRI

Execution Time60.0324ms
Answer
TIMEOUT
InputZantema 06 14

stdout:

TIMEOUT

We consider the following Problem:

  Strict Trs:
    {  b(c(x1)) -> c(x1)
     , a(b(x1)) -> b(a(x1))
     , c(c(x1)) -> c(b(a(x1)))
     , b(b(x1)) -> a(c(b(x1)))
     , a(a(x1)) -> b(a(b(x1)))}
  StartTerms: all
  Strategy: none

Certificate: TIMEOUT

Proof:
  Computation stopped due to timeout after 60.0 seconds.

Arrrr..

Tool TRI2

Execution Time0.17158508ms
Answer
MAYBE
InputZantema 06 14

stdout:

MAYBE

We consider the following Problem:

  Strict Trs:
    {  b(c(x1)) -> c(x1)
     , a(b(x1)) -> b(a(x1))
     , c(c(x1)) -> c(b(a(x1)))
     , b(b(x1)) -> a(c(b(x1)))
     , a(a(x1)) -> b(a(b(x1)))}
  StartTerms: all
  Strategy: none

Certificate: MAYBE

Proof:
  The input cannot be shown compatible

Arrrr..