MAYBE

Problem:
 h(f(x,y)) -> f(f(a(),h(h(y))),x)

Proof:
 DP Processor:
  DPs:
   h#(f(x,y)) -> h#(y)
   h#(f(x,y)) -> h#(h(y))
  TRS:
   h(f(x,y)) -> f(f(a(),h(h(y))),x)
  SCC Processor:
   #sccs: 1
   #rules: 2
   #arcs: 4/4
   DPs:
    h#(f(x,y)) -> h#(y)
    h#(f(x,y)) -> h#(h(y))
   TRS:
    h(f(x,y)) -> f(f(a(),h(h(y))),x)
   Open