MAYBE

Problem:
 f(s(x),y) -> f(x,s(x))
 f(x,s(y)) -> f(y,x)

Proof:
 DP Processor:
  DPs:
   f#(s(x),y) -> f#(x,s(x))
   f#(x,s(y)) -> f#(y,x)
  TRS:
   f(s(x),y) -> f(x,s(x))
   f(x,s(y)) -> f(y,x)
  SCC Processor:
   #sccs: 1
   #rules: 2
   #arcs: 4/4
   DPs:
    f#(s(x),y) -> f#(x,s(x))
    f#(x,s(y)) -> f#(y,x)
   TRS:
    f(s(x),y) -> f(x,s(x))
    f(x,s(y)) -> f(y,x)
   Open