MAYBE

Problem:
 quot(0(),s(y),s(z)) -> 0()
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0(),s(z)) -> s(quot(x,s(z),s(z)))

Proof:
 DP Processor:
  DPs:
   quot#(s(x),s(y),z) -> quot#(x,y,z)
   quot#(x,0(),s(z)) -> quot#(x,s(z),s(z))
  TRS:
   quot(0(),s(y),s(z)) -> 0()
   quot(s(x),s(y),z) -> quot(x,y,z)
   quot(x,0(),s(z)) -> s(quot(x,s(z),s(z)))
  CDG Processor:
   DPs:
    quot#(s(x),s(y),z) -> quot#(x,y,z)
    quot#(x,0(),s(z)) -> quot#(x,s(z),s(z))
   TRS:
    quot(0(),s(y),s(z)) -> 0()
    quot(s(x),s(y),z) -> quot(x,y,z)
    quot(x,0(),s(z)) -> s(quot(x,s(z),s(z)))
   graph:
    quot#(s(x),s(y),z) -> quot#(x,y,z) ->
    quot#(s(x),s(y),z) -> quot#(x,y,z)
    quot#(s(x),s(y),z) -> quot#(x,y,z) ->
    quot#(x,0(),s(z)) -> quot#(x,s(z),s(z))
    quot#(x,0(),s(z)) -> quot#(x,s(z),s(z)) -> quot#(s(x),s(y),z) -> quot#(x,y,z)
   SCC Processor:
    #sccs: 1
    #rules: 2
    #arcs: 3/4
    DPs:
     quot#(s(x),s(y),z) -> quot#(x,y,z)
     quot#(x,0(),s(z)) -> quot#(x,s(z),s(z))
    TRS:
     quot(0(),s(y),s(z)) -> 0()
     quot(s(x),s(y),z) -> quot(x,y,z)
     quot(x,0(),s(z)) -> s(quot(x,s(z),s(z)))
    Open