MAYBE

Problem:
 +(1(),x) -> +(+(0(),1()),x)
 +(0(),x) -> x

Proof:
 DP Processor:
  DPs:
   +#(1(),x) -> +#(0(),1())
   +#(1(),x) -> +#(+(0(),1()),x)
  TRS:
   +(1(),x) -> +(+(0(),1()),x)
   +(0(),x) -> x
  SCC Processor:
   #sccs: 1
   #rules: 2
   #arcs: 4/4
   DPs:
    +#(1(),x) -> +#(0(),1())
    +#(1(),x) -> +#(+(0(),1()),x)
   TRS:
    +(1(),x) -> +(+(0(),1()),x)
    +(0(),x) -> x
   Open