MAYBE

Problem:
 f(a(),f(f(a(),x),a())) -> f(f(a(),f(a(),x)),a())

Proof:
 DP Processor:
  DPs:
   f#(a(),f(f(a(),x),a())) -> f#(a(),f(a(),x))
   f#(a(),f(f(a(),x),a())) -> f#(f(a(),f(a(),x)),a())
  TRS:
   f(a(),f(f(a(),x),a())) -> f(f(a(),f(a(),x)),a())
  SCC Processor:
   #sccs: 1
   #rules: 2
   #arcs: 4/4
   DPs:
    f#(a(),f(f(a(),x),a())) -> f#(a(),f(a(),x))
    f#(a(),f(f(a(),x),a())) -> f#(f(a(),f(a(),x)),a())
   TRS:
    f(a(),f(f(a(),x),a())) -> f(f(a(),f(a(),x)),a())
   Open