MAYBE

Problem:
 p(a(x0),p(a(b(x1)),x2)) -> p(a(b(a(x2))),p(a(a(x1)),x2))

Proof:
 DP Processor:
  DPs:
   p#(a(x0),p(a(b(x1)),x2)) -> p#(a(a(x1)),x2)
   p#(a(x0),p(a(b(x1)),x2)) -> p#(a(b(a(x2))),p(a(a(x1)),x2))
  TRS:
   p(a(x0),p(a(b(x1)),x2)) -> p(a(b(a(x2))),p(a(a(x1)),x2))
  Restore Modifier:
   DPs:
    p#(a(x0),p(a(b(x1)),x2)) -> p#(a(a(x1)),x2)
    p#(a(x0),p(a(b(x1)),x2)) -> p#(a(b(a(x2))),p(a(a(x1)),x2))
   TRS:
    p(a(x0),p(a(b(x1)),x2)) -> p(a(b(a(x2))),p(a(a(x1)),x2))
   SCC Processor:
    #sccs: 1
    #rules: 2
    #arcs: 4/4
    DPs:
     p#(a(x0),p(a(b(x1)),x2)) -> p#(a(a(x1)),x2)
     p#(a(x0),p(a(b(x1)),x2)) -> p#(a(b(a(x2))),p(a(a(x1)),x2))
    TRS:
     p(a(x0),p(a(b(x1)),x2)) -> p(a(b(a(x2))),p(a(a(x1)),x2))
    Open