MAYBE

Problem:
 f(x) -> f(a())

Proof:
 DP Processor:
  DPs:
   f#(x) -> f#(a())
  TRS:
   f(x) -> f(a())
  Usable Rule Processor:
   DPs:
    f#(x) -> f#(a())
   TRS:
    
   Restore Modifier:
    DPs:
     f#(x) -> f#(a())
    TRS:
     f(x) -> f(a())
    SCC Processor:
     #sccs: 1
     #rules: 1
     #arcs: 1/1
     DPs:
      f#(x) -> f#(a())
     TRS:
      f(x) -> f(a())
     Open