MAYBE

Problem:
 f(a()) -> f(a())
 a() -> b()

Proof:
 DP Processor:
  DPs:
   f#(a()) -> f#(a())
  TRS:
   f(a()) -> f(a())
   a() -> b()
  Usable Rule Processor:
   DPs:
    f#(a()) -> f#(a())
   TRS:
    a() -> b()
   Restore Modifier:
    DPs:
     f#(a()) -> f#(a())
    TRS:
     f(a()) -> f(a())
     a() -> b()
    SCC Processor:
     #sccs: 1
     #rules: 1
     #arcs: 1/1
     DPs:
      f#(a()) -> f#(a())
     TRS:
      f(a()) -> f(a())
      a() -> b()
     Open