MAYBE

Problem:
 f(0(),1(),x) -> f(x,x,x)

Proof:
 DP Processor:
  DPs:
   f#(0(),1(),x) -> f#(x,x,x)
  TRS:
   f(0(),1(),x) -> f(x,x,x)
  Usable Rule Processor:
   DPs:
    f#(0(),1(),x) -> f#(x,x,x)
   TRS:
    f4(x,y) -> x
    f4(x,y) -> y
   Restore Modifier:
    DPs:
     f#(0(),1(),x) -> f#(x,x,x)
    TRS:
     f(0(),1(),x) -> f(x,x,x)
    SCC Processor:
     #sccs: 1
     #rules: 1
     #arcs: 1/1
     DPs:
      f#(0(),1(),x) -> f#(x,x,x)
     TRS:
      f(0(),1(),x) -> f(x,x,x)
     Open