MAYBE

Problem:
 2nd(cons(X,cons(Y,Z))) -> Y
 from(X) -> cons(X,from(s(X)))

Proof:
 DP Processor:
  DPs:
   from#(X) -> from#(s(X))
  TRS:
   2nd(cons(X,cons(Y,Z))) -> Y
   from(X) -> cons(X,from(s(X)))
  Usable Rule Processor:
   DPs:
    from#(X) -> from#(s(X))
   TRS:
    
   Restore Modifier:
    DPs:
     from#(X) -> from#(s(X))
    TRS:
     2nd(cons(X,cons(Y,Z))) -> Y
     from(X) -> cons(X,from(s(X)))
    SCC Processor:
     #sccs: 1
     #rules: 1
     #arcs: 1/1
     DPs:
      from#(X) -> from#(s(X))
     TRS:
      2nd(cons(X,cons(Y,Z))) -> Y
      from(X) -> cons(X,from(s(X)))
     Open