YES

Problem:
 p(s(x)) -> x
 fac(0()) -> s(0())
 fac(s(x)) -> times(s(x),fac(p(s(x))))

Proof:
 DP Processor:
  DPs:
   fac#(s(x)) -> p#(s(x))
   fac#(s(x)) -> fac#(p(s(x)))
  TRS:
   p(s(x)) -> x
   fac(0()) -> s(0())
   fac(s(x)) -> times(s(x),fac(p(s(x))))
  Usable Rule Processor:
   DPs:
    fac#(s(x)) -> p#(s(x))
    fac#(s(x)) -> fac#(p(s(x)))
   TRS:
    p(s(x)) -> x
   CDG Processor:
    DPs:
     fac#(s(x)) -> p#(s(x))
     fac#(s(x)) -> fac#(p(s(x)))
    TRS:
     p(s(x)) -> x
    graph:
     
    Qed