MAYBE

Problem:
 f(s(X),Y) -> h(s(f(h(Y),X)))

Proof:
 DP Processor:
  DPs:
   f#(s(X),Y) -> f#(h(Y),X)
  TRS:
   f(s(X),Y) -> h(s(f(h(Y),X)))
  Usable Rule Processor:
   DPs:
    f#(s(X),Y) -> f#(h(Y),X)
   TRS:
    
   Restore Modifier:
    DPs:
     f#(s(X),Y) -> f#(h(Y),X)
    TRS:
     f(s(X),Y) -> h(s(f(h(Y),X)))
    SCC Processor:
     #sccs: 1
     #rules: 1
     #arcs: 1/1
     DPs:
      f#(s(X),Y) -> f#(h(Y),X)
     TRS:
      f(s(X),Y) -> h(s(f(h(Y),X)))
     Open