MAYBE

Problem:
 f(a(),b()) -> f(a(),c())
 f(c(),d()) -> f(b(),d())

Proof:
 DP Processor:
  DPs:
   f#(a(),b()) -> f#(a(),c())
   f#(c(),d()) -> f#(b(),d())
  TRS:
   f(a(),b()) -> f(a(),c())
   f(c(),d()) -> f(b(),d())
  Usable Rule Processor:
   DPs:
    f#(a(),b()) -> f#(a(),c())
    f#(c(),d()) -> f#(b(),d())
   TRS:
    
   Restore Modifier:
    DPs:
     f#(a(),b()) -> f#(a(),c())
     f#(c(),d()) -> f#(b(),d())
    TRS:
     f(a(),b()) -> f(a(),c())
     f(c(),d()) -> f(b(),d())
    SCC Processor:
     #sccs: 1
     #rules: 2
     #arcs: 4/4
     DPs:
      f#(a(),b()) -> f#(a(),c())
      f#(c(),d()) -> f#(b(),d())
     TRS:
      f(a(),b()) -> f(a(),c())
      f(c(),d()) -> f(b(),d())
     Open