YES Problem: a__f(b(),X,c()) -> a__f(X,a__c(),X) a__c() -> b() mark(f(X1,X2,X3)) -> a__f(X1,mark(X2),X3) mark(c()) -> a__c() mark(b()) -> b() a__f(X1,X2,X3) -> f(X1,X2,X3) a__c() -> c() Proof: DP Processor: DPs: a__f#(b(),X,c()) -> a__c#() a__f#(b(),X,c()) -> a__f#(X,a__c(),X) mark#(f(X1,X2,X3)) -> mark#(X2) mark#(f(X1,X2,X3)) -> a__f#(X1,mark(X2),X3) mark#(c()) -> a__c#() TRS: a__f(b(),X,c()) -> a__f(X,a__c(),X) a__c() -> b() mark(f(X1,X2,X3)) -> a__f(X1,mark(X2),X3) mark(c()) -> a__c() mark(b()) -> b() a__f(X1,X2,X3) -> f(X1,X2,X3) a__c() -> c() EDG Processor: DPs: a__f#(b(),X,c()) -> a__c#() a__f#(b(),X,c()) -> a__f#(X,a__c(),X) mark#(f(X1,X2,X3)) -> mark#(X2) mark#(f(X1,X2,X3)) -> a__f#(X1,mark(X2),X3) mark#(c()) -> a__c#() TRS: a__f(b(),X,c()) -> a__f(X,a__c(),X) a__c() -> b() mark(f(X1,X2,X3)) -> a__f(X1,mark(X2),X3) mark(c()) -> a__c() mark(b()) -> b() a__f(X1,X2,X3) -> f(X1,X2,X3) a__c() -> c() graph: mark#(f(X1,X2,X3)) -> mark#(X2) -> mark#(f(X1,X2,X3)) -> mark#(X2) mark#(f(X1,X2,X3)) -> mark#(X2) -> mark#(f(X1,X2,X3)) -> a__f#(X1,mark(X2),X3) mark#(f(X1,X2,X3)) -> mark#(X2) -> mark#(c()) -> a__c#() mark#(f(X1,X2,X3)) -> a__f#(X1,mark(X2),X3) -> a__f#(b(),X,c()) -> a__c#() mark#(f(X1,X2,X3)) -> a__f#(X1,mark(X2),X3) -> a__f#(b(),X,c()) -> a__f#(X,a__c(),X) SCC Processor: #sccs: 1 #rules: 1 #arcs: 5/25 DPs: mark#(f(X1,X2,X3)) -> mark#(X2) TRS: a__f(b(),X,c()) -> a__f(X,a__c(),X) a__c() -> b() mark(f(X1,X2,X3)) -> a__f(X1,mark(X2),X3) mark(c()) -> a__c() mark(b()) -> b() a__f(X1,X2,X3) -> f(X1,X2,X3) a__c() -> c() Matrix Interpretation Processor: dimension: 1 interpretation: [mark#](x0) = x0 + 1, [mark](x0) = x0, [f](x0, x1, x2) = x0 + x1 + 1, [a__c] = 1, [a__f](x0, x1, x2) = x0 + x1 + 1, [c] = 1, [b] = 1 orientation: mark#(f(X1,X2,X3)) = X1 + X2 + 2 >= X2 + 1 = mark#(X2) a__f(b(),X,c()) = X + 2 >= X + 2 = a__f(X,a__c(),X) a__c() = 1 >= 1 = b() mark(f(X1,X2,X3)) = X1 + X2 + 1 >= X1 + X2 + 1 = a__f(X1,mark(X2),X3) mark(c()) = 1 >= 1 = a__c() mark(b()) = 1 >= 1 = b() a__f(X1,X2,X3) = X1 + X2 + 1 >= X1 + X2 + 1 = f(X1,X2,X3) a__c() = 1 >= 1 = c() problem: DPs: TRS: a__f(b(),X,c()) -> a__f(X,a__c(),X) a__c() -> b() mark(f(X1,X2,X3)) -> a__f(X1,mark(X2),X3) mark(c()) -> a__c() mark(b()) -> b() a__f(X1,X2,X3) -> f(X1,X2,X3) a__c() -> c() Qed