YES

Problem:
 __(__(X,Y),Z) -> __(X,__(Y,Z))
 __(X,nil()) -> X
 __(nil(),X) -> X
 and(tt(),X) -> activate(X)
 isNePal(__(I,__(P,I))) -> tt()
 activate(X) -> X

Proof:
 Bounds Processor:
  bound: 0
  enrichment: top
  automaton:
   final states: {7,6,5,4,2,1}
   transitions:
    __0(7,3) -> 6*
    __0(2,3) -> 6*,3,1
    __0(7,7) -> 6*
    __0(2,7) -> 6*
    __0(7,2) -> 6*
    __0(2,2) -> 6*,1,3
    __0(7,6) -> 6*
    __0(2,6) -> 6*
    activate0(7) -> 4*
    activate0(2) -> 4*
    tt0() -> 5*
    f60() -> 7*,4,3,1,2
    1 -> 3*
    2 -> 3,4
    3 -> 1*
    7 -> 4*
  problem:
   
  Qed