YES

Problem:
 h(x,c(y,z)) -> h(c(s(y),x),z)
 h(c(s(x),c(s(0()),y)),z) -> h(y,c(s(0()),c(x,z)))

Proof:
 DP Processor:
  DPs:
   h#(x,c(y,z)) -> h#(c(s(y),x),z)
   h#(c(s(x),c(s(0()),y)),z) -> h#(y,c(s(0()),c(x,z)))
  TRS:
   h(x,c(y,z)) -> h(c(s(y),x),z)
   h(c(s(x),c(s(0()),y)),z) -> h(y,c(s(0()),c(x,z)))
  Bounds Processor:
   bound: 2
   enrichment: match
   automaton:
    final states: {7}
    transitions:
     h1(11,6) -> 6*
     h1(11,15) -> 6*
     h1(6,15) -> 6*
     c1(14,12) -> 15*
     c1(10,11) -> 11*
     c1(10,21) -> 11*
     c1(6,6) -> 12*
     c1(14,15) -> 15*
     c1(10,6) -> 11*
     c1(6,15) -> 12*
     s1(6) -> 10*
     s1(13) -> 14*
     01() -> 13*
     h{#,1}(11,6) -> 7*
     h{#,1}(11,15) -> 7*
     h{#,1}(6,15) -> 7*
     h2(19,12) -> 6*
     h2(21,6) -> 6*
     h2(19,15) -> 6*
     h2(21,15) -> 6*
     h{#,0}(6,6) -> 7*
     c2(18,11) -> 19*
     c2(18,19) -> 19*
     c2(18,21) -> 19*
     c2(20,19) -> 21*
     c2(18,6) -> 19*
     c0(6,6) -> 6*
     s2(14) -> 18*
     s2(6) -> 20*
     s0(6) -> 6*
     h{#,2}(19,12) -> 7*
     h{#,2}(21,6) -> 7*
     h{#,2}(19,15) -> 7*
     h{#,2}(21,15) -> 7*
     00() -> 6*
     h0(6,6) -> 6*
   problem:
    DPs:
     
    TRS:
     h(x,c(y,z)) -> h(c(s(y),x),z)
     h(c(s(x),c(s(0()),y)),z) -> h(y,c(s(0()),c(x,z)))
   Qed