YES

Problem:
 f(a(),f(x,a())) -> f(x,f(f(a(),a()),a()))

Proof:
 DP Processor:
  DPs:
   f#(a(),f(x,a())) -> f#(a(),a())
   f#(a(),f(x,a())) -> f#(f(a(),a()),a())
   f#(a(),f(x,a())) -> f#(x,f(f(a(),a()),a()))
  TRS:
   f(a(),f(x,a())) -> f(x,f(f(a(),a()),a()))
  EDG Processor:
   DPs:
    f#(a(),f(x,a())) -> f#(a(),a())
    f#(a(),f(x,a())) -> f#(f(a(),a()),a())
    f#(a(),f(x,a())) -> f#(x,f(f(a(),a()),a()))
   TRS:
    f(a(),f(x,a())) -> f(x,f(f(a(),a()),a()))
   graph:
    f#(a(),f(x,a())) -> f#(x,f(f(a(),a()),a())) ->
    f#(a(),f(x,a())) -> f#(a(),a())
    f#(a(),f(x,a())) -> f#(x,f(f(a(),a()),a())) ->
    f#(a(),f(x,a())) -> f#(f(a(),a()),a())
    f#(a(),f(x,a())) -> f#(x,f(f(a(),a()),a())) -> f#(a(),f(x,a())) -> f#(x,f(f(a(),a()),a()))
   SCC Processor:
    #sccs: 1
    #rules: 1
    #arcs: 3/9
    DPs:
     f#(a(),f(x,a())) -> f#(x,f(f(a(),a()),a()))
    TRS:
     f(a(),f(x,a())) -> f(x,f(f(a(),a()),a()))
    Usable Rule Processor:
     DPs:
      f#(a(),f(x,a())) -> f#(x,f(f(a(),a()),a()))
     TRS:
      
     Bounds Processor:
      bound: 1
      enrichment: match
      automaton:
       final states: {5}
       transitions:
        f{#,1}(10,11) -> 5*
        f{#,1}(4,11) -> 5*
        f1(10,9) -> 11*
        f1(9,9) -> 10*
        a1() -> 9*
        f{#,0}(4,4) -> 5*
        a0() -> 4*
        f0(4,4) -> 4*
      problem:
       DPs:
        
       TRS:
        
      Qed