YES Problem: and(x,false()) -> false() and(x,not(false())) -> x not(not(x)) -> x implies(false(),y) -> not(false()) implies(x,false()) -> not(x) implies(not(x),not(y)) -> implies(y,and(x,y)) Proof: DP Processor: DPs: implies#(false(),y) -> not#(false()) implies#(x,false()) -> not#(x) implies#(not(x),not(y)) -> and#(x,y) implies#(not(x),not(y)) -> implies#(y,and(x,y)) TRS: and(x,false()) -> false() and(x,not(false())) -> x not(not(x)) -> x implies(false(),y) -> not(false()) implies(x,false()) -> not(x) implies(not(x),not(y)) -> implies(y,and(x,y)) EDG Processor: DPs: implies#(false(),y) -> not#(false()) implies#(x,false()) -> not#(x) implies#(not(x),not(y)) -> and#(x,y) implies#(not(x),not(y)) -> implies#(y,and(x,y)) TRS: and(x,false()) -> false() and(x,not(false())) -> x not(not(x)) -> x implies(false(),y) -> not(false()) implies(x,false()) -> not(x) implies(not(x),not(y)) -> implies(y,and(x,y)) graph: implies#(not(x),not(y)) -> implies#(y,and(x,y)) -> implies#(false(),y) -> not#(false()) implies#(not(x),not(y)) -> implies#(y,and(x,y)) -> implies#(x,false()) -> not#(x) implies#(not(x),not(y)) -> implies#(y,and(x,y)) -> implies#(not(x),not(y)) -> and#(x,y) implies#(not(x),not(y)) -> implies#(y,and(x,y)) -> implies#(not(x),not(y)) -> implies#(y,and(x,y)) SCC Processor: #sccs: 1 #rules: 1 #arcs: 4/16 DPs: implies#(not(x),not(y)) -> implies#(y,and(x,y)) TRS: and(x,false()) -> false() and(x,not(false())) -> x not(not(x)) -> x implies(false(),y) -> not(false()) implies(x,false()) -> not(x) implies(not(x),not(y)) -> implies(y,and(x,y)) Matrix Interpretation Processor: dimension: 1 interpretation: [implies#](x0, x1) = x0 + x1 + 1, [implies](x0, x1) = x0 + x1 + 1, [not](x0) = x0 + 1, [and](x0, x1) = x0, [false] = 0 orientation: implies#(not(x),not(y)) = x + y + 3 >= x + y + 1 = implies#(y,and(x,y)) and(x,false()) = x >= 0 = false() and(x,not(false())) = x >= x = x not(not(x)) = x + 2 >= x = x implies(false(),y) = y + 1 >= 1 = not(false()) implies(x,false()) = x + 1 >= x + 1 = not(x) implies(not(x),not(y)) = x + y + 3 >= x + y + 1 = implies(y,and(x,y)) problem: DPs: TRS: and(x,false()) -> false() and(x,not(false())) -> x not(not(x)) -> x implies(false(),y) -> not(false()) implies(x,false()) -> not(x) implies(not(x),not(y)) -> implies(y,and(x,y)) Qed