YES

Problem:
 f(f(a(),a()),x) -> f(f(x,a()),f(a(),f(a(),a())))

Proof:
 DP Processor:
  DPs:
   f#(f(a(),a()),x) -> f#(a(),f(a(),a()))
   f#(f(a(),a()),x) -> f#(x,a())
   f#(f(a(),a()),x) -> f#(f(x,a()),f(a(),f(a(),a())))
  TRS:
   f(f(a(),a()),x) -> f(f(x,a()),f(a(),f(a(),a())))
  EDG Processor:
   DPs:
    f#(f(a(),a()),x) -> f#(a(),f(a(),a()))
    f#(f(a(),a()),x) -> f#(x,a())
    f#(f(a(),a()),x) -> f#(f(x,a()),f(a(),f(a(),a())))
   TRS:
    f(f(a(),a()),x) -> f(f(x,a()),f(a(),f(a(),a())))
   graph:
    f#(f(a(),a()),x) -> f#(f(x,a()),f(a(),f(a(),a()))) ->
    f#(f(a(),a()),x) -> f#(a(),f(a(),a()))
    f#(f(a(),a()),x) -> f#(f(x,a()),f(a(),f(a(),a()))) ->
    f#(f(a(),a()),x) -> f#(x,a())
    f#(f(a(),a()),x) -> f#(f(x,a()),f(a(),f(a(),a()))) ->
    f#(f(a(),a()),x) -> f#(f(x,a()),f(a(),f(a(),a())))
    f#(f(a(),a()),x) -> f#(x,a()) ->
    f#(f(a(),a()),x) -> f#(a(),f(a(),a()))
    f#(f(a(),a()),x) -> f#(x,a()) -> f#(f(a(),a()),x) -> f#(x,a())
    f#(f(a(),a()),x) -> f#(x,a()) -> f#(f(a(),a()),x) -> f#(f(x,a()),f(a(),f(a(),a())))
   SCC Processor:
    #sccs: 1
    #rules: 2
    #arcs: 6/9
    DPs:
     f#(f(a(),a()),x) -> f#(f(x,a()),f(a(),f(a(),a())))
     f#(f(a(),a()),x) -> f#(x,a())
    TRS:
     f(f(a(),a()),x) -> f(f(x,a()),f(a(),f(a(),a())))
    Bounds Processor:
     bound: 1
     enrichment: match-dp
     automaton:
      final states: {7}
      transitions:
       f0(8,8) -> 9,10
       f0(8,10) -> 8*
       a0() -> 8*
       f{#,1}(8,11) -> 7*
       a1() -> 11*
       f30() -> 9*
       f{#,0}(9,8) -> 7*
     problem:
      DPs:
       f#(f(a(),a()),x) -> f#(f(x,a()),f(a(),f(a(),a())))
      TRS:
       f(f(a(),a()),x) -> f(f(x,a()),f(a(),f(a(),a())))
     Bounds Processor:
      bound: 0
      enrichment: match-dp
      automaton:
       final states: {1}
       transitions:
        f100() -> 5*
        f{#,0}(6,4) -> 1*
        f0(4,2) -> 6*
        f0(6,4) -> 6*
        f0(2,3) -> 4*
        f0(3,4) -> 6*
        f0(5,2) -> 6*
        f0(2,2) -> 3*
        a0() -> 2*
      problem:
       DPs:
        
       TRS:
        f(f(a(),a()),x) -> f(f(x,a()),f(a(),f(a(),a())))
      Qed