YES(?,O(n^2))

Problem:
 minus(minus(x)) -> x
 minus(h(x)) -> h(minus(x))
 minus(f(x,y)) -> f(minus(y),minus(x))

Proof:
 Matrix Interpretation Processor:
  dimension: 2
  interpretation:
                           [2]
   [f](x0, x1) = x0 + x1 + [2],
   
             [1 4]     [1 ]
   [h](x0) = [0 1]x0 + [14],
   
                 [1 2]     [1]
   [minus](x0) = [0 1]x0 + [0]
  orientation:
                     [1 4]    [2]         
   minus(minus(x)) = [0 1]x + [0] >= x = x
   
                 [1 6]    [30]    [1 6]    [2 ]              
   minus(h(x)) = [0 1]x + [14] >= [0 1]x + [14] = h(minus(x))
   
                   [1 2]    [1 2]    [7]    [1 2]    [1 2]    [4]                       
   minus(f(x,y)) = [0 1]x + [0 1]y + [2] >= [0 1]x + [0 1]y + [2] = f(minus(y),minus(x))
  problem:
   
  Qed