YES(?,O(n^1))

Problem:
 d(x) -> e(u(x))
 d(u(x)) -> c(x)
 c(u(x)) -> b(x)
 v(e(x)) -> x
 b(u(x)) -> a(e(x))

Proof:
 RT Transformation Processor:
  strict:
   d(x) -> e(u(x))
   d(u(x)) -> c(x)
   c(u(x)) -> b(x)
   v(e(x)) -> x
   b(u(x)) -> a(e(x))
  weak:
   
  Matrix Interpretation Processor:
   dimension: 1
   interpretation:
    [a](x0) = x0 + 15,
    
    [v](x0) = x0 + 15,
    
    [b](x0) = x0 + 3,
    
    [c](x0) = x0 + 2,
    
    [e](x0) = x0 + 1,
    
    [u](x0) = x0 + 16,
    
    [d](x0) = x0
   orientation:
    d(x) = x >= x + 17 = e(u(x))
    
    d(u(x)) = x + 16 >= x + 2 = c(x)
    
    c(u(x)) = x + 18 >= x + 3 = b(x)
    
    v(e(x)) = x + 16 >= x = x
    
    b(u(x)) = x + 19 >= x + 16 = a(e(x))
   problem:
    strict:
     d(x) -> e(u(x))
    weak:
     d(u(x)) -> c(x)
     c(u(x)) -> b(x)
     v(e(x)) -> x
     b(u(x)) -> a(e(x))
   Matrix Interpretation Processor:
    dimension: 1
    interpretation:
     [a](x0) = x0 + 19,
     
     [v](x0) = x0,
     
     [b](x0) = x0 + 31,
     
     [c](x0) = x0 + 29,
     
     [e](x0) = x0 + 14,
     
     [u](x0) = x0 + 2,
     
     [d](x0) = x0 + 27
    orientation:
     d(x) = x + 27 >= x + 16 = e(u(x))
     
     d(u(x)) = x + 29 >= x + 29 = c(x)
     
     c(u(x)) = x + 31 >= x + 31 = b(x)
     
     v(e(x)) = x + 14 >= x = x
     
     b(u(x)) = x + 33 >= x + 33 = a(e(x))
    problem:
     strict:
      
     weak:
      d(x) -> e(u(x))
      d(u(x)) -> c(x)
      c(u(x)) -> b(x)
      v(e(x)) -> x
      b(u(x)) -> a(e(x))
    Qed