MAYBE

Problem:
 a(x1) -> x1
 a(b(x1)) -> b(b(a(c(x1))))
 b(b(x1)) -> x1
 c(c(x1)) -> a(x1)

Proof:
 RT Transformation Processor:
  strict:
   a(x1) -> x1
   a(b(x1)) -> b(b(a(c(x1))))
   b(b(x1)) -> x1
   c(c(x1)) -> a(x1)
  weak:
   
  Matrix Interpretation Processor:
   dimension: 1
   interpretation:
    [c](x0) = x0 + 1,
    
    [b](x0) = x0 + 2,
    
    [a](x0) = x0 + 1
   orientation:
    a(x1) = x1 + 1 >= x1 = x1
    
    a(b(x1)) = x1 + 3 >= x1 + 6 = b(b(a(c(x1))))
    
    b(b(x1)) = x1 + 4 >= x1 = x1
    
    c(c(x1)) = x1 + 2 >= x1 + 1 = a(x1)
   problem:
    strict:
     a(b(x1)) -> b(b(a(c(x1))))
    weak:
     a(x1) -> x1
     b(b(x1)) -> x1
     c(c(x1)) -> a(x1)
   Open