MAYBE Problem: a(a(x1)) -> b(b(b(x1))) b(x1) -> c(c(d(x1))) c(x1) -> d(d(d(x1))) b(c(x1)) -> c(b(x1)) b(c(d(x1))) -> a(x1) Proof: RT Transformation Processor: strict: a(a(x1)) -> b(b(b(x1))) b(x1) -> c(c(d(x1))) c(x1) -> d(d(d(x1))) b(c(x1)) -> c(b(x1)) b(c(d(x1))) -> a(x1) weak: Matrix Interpretation Processor: dimension: 1 interpretation: [c](x0) = x0 + 9, [d](x0) = x0 + 5, [b](x0) = x0 + 1, [a](x0) = x0 + 16 orientation: a(a(x1)) = x1 + 32 >= x1 + 3 = b(b(b(x1))) b(x1) = x1 + 1 >= x1 + 23 = c(c(d(x1))) c(x1) = x1 + 9 >= x1 + 15 = d(d(d(x1))) b(c(x1)) = x1 + 10 >= x1 + 10 = c(b(x1)) b(c(d(x1))) = x1 + 15 >= x1 + 16 = a(x1) problem: strict: b(x1) -> c(c(d(x1))) c(x1) -> d(d(d(x1))) b(c(x1)) -> c(b(x1)) b(c(d(x1))) -> a(x1) weak: a(a(x1)) -> b(b(b(x1))) Matrix Interpretation Processor: dimension: 1 interpretation: [c](x0) = x0 + 17, [d](x0) = x0 + 16, [b](x0) = x0, [a](x0) = x0 orientation: b(x1) = x1 >= x1 + 50 = c(c(d(x1))) c(x1) = x1 + 17 >= x1 + 48 = d(d(d(x1))) b(c(x1)) = x1 + 17 >= x1 + 17 = c(b(x1)) b(c(d(x1))) = x1 + 33 >= x1 = a(x1) a(a(x1)) = x1 >= x1 = b(b(b(x1))) problem: strict: b(x1) -> c(c(d(x1))) c(x1) -> d(d(d(x1))) b(c(x1)) -> c(b(x1)) weak: b(c(d(x1))) -> a(x1) a(a(x1)) -> b(b(b(x1))) Matrix Interpretation Processor: dimension: 1 interpretation: [c](x0) = x0 + 16, [d](x0) = x0 + 2, [b](x0) = x0 + 16, [a](x0) = x0 + 24 orientation: b(x1) = x1 + 16 >= x1 + 34 = c(c(d(x1))) c(x1) = x1 + 16 >= x1 + 6 = d(d(d(x1))) b(c(x1)) = x1 + 32 >= x1 + 32 = c(b(x1)) b(c(d(x1))) = x1 + 34 >= x1 + 24 = a(x1) a(a(x1)) = x1 + 48 >= x1 + 48 = b(b(b(x1))) problem: strict: b(x1) -> c(c(d(x1))) b(c(x1)) -> c(b(x1)) weak: c(x1) -> d(d(d(x1))) b(c(d(x1))) -> a(x1) a(a(x1)) -> b(b(b(x1))) Matrix Interpretation Processor: dimension: 1 interpretation: [c](x0) = x0 + 4, [d](x0) = x0 + 1, [b](x0) = x0 + 10, [a](x0) = x0 + 15 orientation: b(x1) = x1 + 10 >= x1 + 9 = c(c(d(x1))) b(c(x1)) = x1 + 14 >= x1 + 14 = c(b(x1)) c(x1) = x1 + 4 >= x1 + 3 = d(d(d(x1))) b(c(d(x1))) = x1 + 15 >= x1 + 15 = a(x1) a(a(x1)) = x1 + 30 >= x1 + 30 = b(b(b(x1))) problem: strict: b(c(x1)) -> c(b(x1)) weak: b(x1) -> c(c(d(x1))) c(x1) -> d(d(d(x1))) b(c(d(x1))) -> a(x1) a(a(x1)) -> b(b(b(x1))) Open