YES
Time: 0.017

Problem:
 Equations:
  plusAC(plusAC(x3,x4),x5) -> plusAC(x3,plusAC(x4,x5))
  plusAC(x3,x4) -> plusAC(x4,x3)
  plusAC(x3,plusAC(x4,x5)) -> plusAC(plusAC(x3,x4),x5)
  plusAC(x4,x3) -> plusAC(x3,x4)
 TRS:
  s(p(x)) -> x
  p(s(x)) -> x
  minus(x,0()) -> x
  minus(x,s(y)) -> p(minus(x,y))
  minus(x,p(y)) -> s(minus(x,y))
  plusAC(x,0()) -> x
  plusAC(x,s(y)) -> s(plusAC(x,y))
  plusAC(x,p(y)) -> p(plusAC(x,y))

Proof:
 AC-RPO Processor:
  precedence:
   minus > 0 > plusAC > s > p
  status:
   minus:mul  
  problem:
   Equations:
    plusAC(plusAC(x3,x4),x5) -> plusAC(x3,plusAC(x4,x5))
    plusAC(x3,x4) -> plusAC(x4,x3)
    plusAC(x3,plusAC(x4,x5)) -> plusAC(plusAC(x3,x4),x5)
    plusAC(x4,x3) -> plusAC(x3,x4)
   TRS:
    
  Qed