MAYBE
Time: 0.012

Problem:
 Equations:
  plusAC(plusAC(x2,x3),x4) -> plusAC(x2,plusAC(x3,x4))
  plusAC(x2,x3) -> plusAC(x3,x2)
  plusAC(x2,plusAC(x3,x4)) -> plusAC(plusAC(x2,x3),x4)
  plusAC(x3,x2) -> plusAC(x2,x3)
 TRS:
  minus(plusAC(x,y),y) -> x
  dix(zero(),s(y)) -> 0()
  div(s(x),s(y)) -> s(div(minus(x,y),s(y)))
  plusAC(0(),x) -> x
  plusAC(s(x),y) -> s(plusAC(x,y))

Proof:
 Open