YES
Time: 0.009

Problem:
 Equations:
  meetAC(meetAC(x1,x2),x3) -> meetAC(x1,meetAC(x2,x3))
  meetAC(x1,x2) -> meetAC(x2,x1)
  meetAC(x1,meetAC(x2,x3)) -> meetAC(meetAC(x1,x2),x3)
  meetAC(x2,x1) -> meetAC(x1,x2)
 TRS:
  meetAC(x,x) -> x

Proof:
 AC-RPO Processor:
  precedence:
   meetAC
  status:
   
  problem:
   Equations:
    meetAC(meetAC(x1,x2),x3) -> meetAC(x1,meetAC(x2,x3))
    meetAC(x1,x2) -> meetAC(x2,x1)
    meetAC(x1,meetAC(x2,x3)) -> meetAC(meetAC(x1,x2),x3)
    meetAC(x2,x1) -> meetAC(x1,x2)
   TRS:
    
  Qed