YES
Time: 0.007

Problem:
 Equations:
  meetAC(meetAC(x1,x2),x3) -> meetAC(x1,meetAC(x2,x3))
  meetAC(x1,x2) -> meetAC(x2,x1)
  meetAC(x1,meetAC(x2,x3)) -> meetAC(meetAC(x1,x2),x3)
  meetAC(x2,x1) -> meetAC(x1,x2)
 TRS:
  meetAC(x,x) -> x

Proof:
 AC-KBO Processor:
  precedence:
   meetAC
   weight function:
    w0 = 4
    w(meetAC) = 0
   problem:
    Equations:
     meetAC(meetAC(x1,x2),x3) -> meetAC(x1,meetAC(x2,x3))
     meetAC(x1,x2) -> meetAC(x2,x1)
     meetAC(x1,meetAC(x2,x3)) -> meetAC(meetAC(x1,x2),x3)
     meetAC(x2,x1) -> meetAC(x1,x2)
    TRS:
     
   Qed