YES
Time: 0.075

Problem:
 Equations:
  plusAC(plusAC(x3,x4),x5) -> plusAC(x3,plusAC(x4,x5))
  plusAC(x3,x4) -> plusAC(x4,x3)
  plusAC(x3,plusAC(x4,x5)) -> plusAC(plusAC(x3,x4),x5)
  plusAC(x4,x3) -> plusAC(x3,x4)
 TRS:
  s(p(x)) -> x
  p(s(x)) -> x
  minus(x,0()) -> x
  minus(x,s(y)) -> p(minus(x,y))
  minus(x,p(y)) -> s(minus(x,y))
  plusAC(x,0()) -> x
  plusAC(x,s(y)) -> s(plusAC(x,y))
  plusAC(x,p(y)) -> p(plusAC(x,y))

Proof:
 AC-KBO Processor:
  precedence:
   plusAC > minus ~ 0 ~ s ~ p
   weight function:
    [minus](x0, x1) = 8x0 + 9x1 + 8,
    
    [0] = 1,
    
    [s](x0) = x0 + 8,
    
    [p](x0) = x0 + 2,
    
    [plusAC](x0, x1) = x0 + x1
   problem:
    Equations:
     plusAC(plusAC(x3,x4),x5) -> plusAC(x3,plusAC(x4,x5))
     plusAC(x3,x4) -> plusAC(x4,x3)
     plusAC(x3,plusAC(x4,x5)) -> plusAC(plusAC(x3,x4),x5)
     plusAC(x4,x3) -> plusAC(x3,x4)
    TRS:
     
   Qed