YES
Time: 0.029

Problem:
 Equations:
  fAC(fAC(x1,x2),x3) -> fAC(x1,fAC(x2,x3))
  fAC(x1,x2) -> fAC(x2,x1)
  fAC(x1,fAC(x2,x3)) -> fAC(fAC(x1,x2),x3)
  fAC(x2,x1) -> fAC(x1,x2)
 TRS:
  fAC(g(g(x)),x) -> fAC(g(x),g(x))
  fAC(fAC(x,x),g(x)) -> fAC(x,h(x))

Proof:
 AC-KBO Processor:
  precedence:
   h ~ fAC > g
   weight function:
    [h](x0) = 2x0 + 11,
    
    [g](x0) = x0 + 6,
    
    [fAC](x0, x1) = x0 + x1 + 10
   problem:
    Equations:
     fAC(fAC(x1,x2),x3) -> fAC(x1,fAC(x2,x3))
     fAC(x1,x2) -> fAC(x2,x1)
     fAC(x1,fAC(x2,x3)) -> fAC(fAC(x1,x2),x3)
     fAC(x2,x1) -> fAC(x1,x2)
    TRS:
     
   Qed