MAYBE
Time: 0.024

Problem:
 Equations:
  plusAC(plusAC(x3,x4),x5) -> plusAC(x3,plusAC(x4,x5))
  plusAC(x3,x4) -> plusAC(x4,x3)
  timesAC(timesAC(x3,x4),x5) -> timesAC(x3,timesAC(x4,x5))
  timesAC(x3,x4) -> timesAC(x4,x3)
  plusAC(x3,plusAC(x4,x5)) -> plusAC(plusAC(x3,x4),x5)
  plusAC(x4,x3) -> plusAC(x3,x4)
  timesAC(x3,timesAC(x4,x5)) -> timesAC(timesAC(x3,x4),x5)
  timesAC(x4,x3) -> timesAC(x3,x4)
 TRS:
  plusAC(x,0()) -> x
  plusAC(x,s(y)) -> s(plusAC(x,y))
  plusAC(x,plusAC(s(y),z)) -> plusAC(s(plusAC(x,y)),z)
  timesAC(x,0()) -> 0()
  timesAC(x,timesAC(0(),z)) -> timesAC(0(),z)
  timesAC(x,s(y)) -> plusAC(timesAC(x,y),x)
  timesAC(x,timesAC(s(y),z)) -> timesAC(plusAC(timesAC(x,y),x),z)

Proof:
 Open