MAYBE
Time: 0.285

Problem:
 Equations:
  plusAC(plusAC(x2,x3),x4) -> plusAC(x2,plusAC(x3,x4))
  plusAC(x2,x3) -> plusAC(x3,x2)
  plusAC(x2,plusAC(x3,x4)) -> plusAC(plusAC(x2,x3),x4)
  plusAC(x3,x2) -> plusAC(x2,x3)
 TRS:
  zero(sharp()) -> sharp()
  plusAC(x,sharp()) -> x
  plusAC(zero(x),zero(y)) -> zero(plusAC(x,y))
  plusAC(zero(x),one(y)) -> one(plusAC(x,y))
  plusAC(one(x),one(y)) -> j(plusAC(x,plusAC(y,one(sharp()))))
  plusAC(zero(x),j(y)) -> j(plusAC(x,y))
  plusAC(j(x),one(y)) -> zero(plusAC(x,y))
  plusAC(j(x),j(y)) -> one(plusAC(x,plusAC(y,j(sharp()))))

Proof:
 Open