YES
Time: 0.009

Problem:
 Equations:
  meetAC(meetAC(x1,x2),x3) -> meetAC(x1,meetAC(x2,x3))
  meetAC(x1,x2) -> meetAC(x2,x1)
  meetAC(x1,meetAC(x2,x3)) -> meetAC(meetAC(x1,x2),x3)
  meetAC(x2,x1) -> meetAC(x1,x2)
 TRS:
  meetAC(x,x) -> x

Proof:
 Matrix Interpretation Processor:
  dimension: 1
  interpretation:
   [meetAC](x0, x1) = x0 + x1 + 1
  orientation:
   meetAC(x,x) = 2x + 1 >= x = x
  problem:
   Equations:
    meetAC(meetAC(x1,x2),x3) -> meetAC(x1,meetAC(x2,x3))
    meetAC(x1,x2) -> meetAC(x2,x1)
    meetAC(x1,meetAC(x2,x3)) -> meetAC(meetAC(x1,x2),x3)
    meetAC(x2,x1) -> meetAC(x1,x2)
   TRS:
    
  Qed