YES
Time: 0.012

Problem:
 Equations:
  
 TRS:
  andAC(x,0()) -> 0()
  andAC(x,1()) -> x
  andAC(x,x) -> x
  orAC(x,0()) -> x
  orAC(x,1()) -> 1()
  orAC(x,x) -> x

Proof:
 AC-KBO Processor:
  precedence:
   0 > orAC > 1 > andAC
   weight function:
    w0 = 1
    w(0) = 4
    w(1) = 2
    w(orAC) = w(andAC) = 0
   problem:
    Equations:
     
    TRS:
     
   Qed