YES
Time: 0.124

Problem:
 Equations:
  
 TRS:
  plus(x,0()) -> x
  plus(x,s(y)) -> s(plus(x,y))
  minAC(0(),y) -> 0()
  minAC(s(x),s(y)) -> s(minAC(x,y))
  maxAC(0(),y) -> y
  maxAC(s(x),s(y)) -> s(maxAC(x,y))

Proof:
 AC-KBO Processor:
  precedence:
   maxAC > 0 > plus > s > minAC
   weight function:
    [s](x0) = x0 + 8,
    
    [plus](x0, x1) = 8x0 + x1,
    
    [0] = 2,
    
    [maxAC](x0, x1) = x0 + x1 + 4,
    
    [minAC](x0, x1) = x0 + x1 + 13
   problem:
    Equations:
     
    TRS:
     
   Qed