YES
Time: 0.009

Problem:
 Equations:
  
 TRS:
  andAC(x,0()) -> 0()
  andAC(x,1()) -> x
  andAC(x,x) -> x
  orAC(x,0()) -> x
  orAC(x,1()) -> 1()
  orAC(x,x) -> x

Proof:
 AC-KBO Processor:
  precedence:
   0 > orAC > 1 > andAC
   weight function:
    [1] = 1,
    
    [0] = 1,
    
    [orAC](x0, x1) = x0 + x1,
    
    [andAC](x0, x1) = x0 + x1
   problem:
    Equations:
     
    TRS:
     
   Qed