YES
Time: 0.084

Problem:
 Equations:
  
 TRS:
  f(plusAC(x,y)) -> plusAC(f(x),f(y))
  plusAC(x,0()) -> 0()
  f(0()) -> 0()

Proof:
 AC-KBO Processor:
  precedence:
   f > 0 ~ plusAC
   weight function:
    [0] = 8,
    
    [f](x0) = 2x0 + 1,
    
    [plusAC](x0, x1) = x0 + x1 + 1
   problem:
    Equations:
     
    TRS:
     
   Qed